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primu2002
.amico.

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Question Applicazione della Resolution

Raga qualcuno riesce a spiegarmi l'applicazione della regola? Non capisco che razza di sostituzione faccia!!!!!

24[0:Inp] || snail(U) -> plant(snail_food_of(U))*.
303[0:MRR:298.0,8.0] || plant(U)+ -> eats(a_fox,a_bird)* eats(a_fox,U)*.

305[0:Res:24.1,303.0] || snail(U) -> eats(a_fox,a_bird) eats(a_fox,snail_food_of(U))*.

Non dovrebbe essere U=snail_food_of(U)? Allora perchè snail(U) rimane snail(U) e non diventa snail_food_of(snail(U))?

23-02-2009 18:19
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primu2002
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oppure:

19[0:Inp] || snail(U) bird(V) -> much_smaller(U,V)*.
25[0:Inp] || animal(U) plant(V) animal(W) plant(X) much_smaller(W,U)+ eats(W,X)* -> eats(U,V)* eats(U,W)*.
59[0:Res:19.2,25.4] || snail(U) bird(V) animal(V) plant(W) animal(U) plant(X) eats(U,X)* -> eats(V,W)* eats(V,U)*. Non dovrebbe essere W=U U=V ?

23-02-2009 18:40
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NoWhereMan
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vado di fretta, ma velocemente:

non farti ingannare dai nomi delle variabili, ogni variabile (spero di non dire scemenze :D) all'interno delle diverse clausole è da considerarsi diversa

vale a dire

c1 P(X)
c2 M(X)

X non è la stessa variabile, è un qualsiasi X, quel che conta per unificare sono i predicati e le funzioni

se fai fatica a vederlo, prova prima a rinominare su un foglio tutte le variabili della seconda clausola, per capire il meccanismo

questo per quanto riguarda il primo esempio, nel secondo credo il problema sia analogo anche se non ho dato un'occhiata approfondita

ciao

23-02-2009 19:37
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primu2002
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fantastico! Provo subito!
Grazie 1.000,99!!

23-02-2009 21:14
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primu2002
.amico.

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fantastico! Provo subito!
Grazie 1.000,99!!

[Diego grazie anche a te!!]

23-02-2009 21:14
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