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Batti
.novellino.

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 esercizio congruenza

ciao a tutti

qualcuno potrebbe darmi una dritta per risolvere questo esercizio?

12x congruo -5(mod41)

MCD(12, 41) = 1 -> c'è una soluzione
1|-5 quindi ammette una soluzione
imposto l'equazione diofantea così:
12x +41y =-5
come faccio a risolverla? mi blocco in questo punto

ciao
30-06-2011 14:05
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Batti
.novellino.

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Registered: Jun 2010
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Time Online: 1:25:08: [...]
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ho risolto io:

12=41*0+12
41=12*3+5
12=5*2+2
5=2*2+1
2=1*2+0

1=5-2*2=5-(12-5*2)*2=41-12*3-12*2-5*4=41-12*5-(41-12*3)*4=41*5-12*17

x=17
17*-5=-85

la soluzione è una ed è -85
02-07-2011 15:06
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