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.dsy:it. : Powered by vBulletin version 2.3.1 .dsy:it. > Didattica > Corsi A - F > Calcolo delle probabilità e statistica matematica > Esame 02 - Aprile
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Java
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eh mi baso solo sul grafico però sull'80 sono abbastanza sicuro

il IV.1 ok

il IV.2 uso la E(|X*|^3)/sqrt n; tu cosa hai usato scusa?

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08-04-2008 16:42
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oscar
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ok es4/2 = 0.126 con stessa formula a posto ora è il es3/1 che mi preoccupa!!!

08-04-2008 16:46
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Java
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se tu guardi il Grafico b vedi che la funzione va a 1 quando arriva a 80 esattamente come nel grafico II.3 quando a 3 va a uno e infatti la n lì vale 3...mentre per la p ti basi sul terzo grafico suppongo

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08-04-2008 16:49
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oscar
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sembrerebbe la p= circa 0.7 o poco + ma non ci metto la mano sul fuoco

08-04-2008 16:50
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oscar
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60/80= 0.75 mi sembra il + quotato per la p

08-04-2008 16:52
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Java
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comunque la IV.3 io ho semplicemente isolato la n ma non so se sia giusto

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08-04-2008 16:53
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GiKappa
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anche io per la IV.3 ho isolato la n e mi esce uguale a (p^2 + q^2)^2/(E sqrt(pq))^2

e nel IV.4 n quanto vi esce?

per il III.1 avete guardato solo i grafici?

Last edited by GiKappa on 08-04-2008 at 18:18

08-04-2008 17:02
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oscar
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a me la n nel es4/4 viene 1.6*10^6

08-04-2008 17:07
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il Iv.4 secondo me è infinito....

il IV.3 mi esce (p^2 + q^2)^2/(sqrt(p*q)*Epsilon)^2 non capisco la tua px????

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08-04-2008 17:09
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scusate ancora ma l'esercizio IV.1 oscar hai detto di confrontare il 0.53766 coi 2 valori trovati sulle tavole ma nel testo cè scritto che il 0.53766 lo ha trovato con n=100 e p=0.7 mentre ci chiede l'approssimazione per n e p di III.1!!!!!!

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08-04-2008 17:18
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GiKappa
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Originally posted by Java
il Iv.4 secondo me è infinito....

il IV.3 mi esce (p^2 + q^2)^2/(sqrt(p*q)*Epsilon)^2 non capisco la tua px????


ho sbagliato! volevo dire pq, non px!

08-04-2008 17:32
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Java
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perfetto

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08-04-2008 17:47
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GiKappa
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anche a me IV.4 esce 1,6 * 10^8, quindi 160 * 10^6, cioè qualche milione.

ho sostituito p = 0,7 e epsilon = 10^-4

08-04-2008 18:22
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oscar
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perfetto 160 milioni pure a me!

08-04-2008 18:30
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confermo 160 milioni

ma l'esercizio IV.1 hai detto di confrontare il 0.53766 coi 2 valori trovati sulle tavole ma nel testo cè scritto che il 0.53766 lo ha trovato con n=100 e p=0.7 mentre ci chiede l'approssimazione per n e p di III.1!!!!!!

ergo i valori del III.1 sono per forza 100 e 0.7???

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08-04-2008 18:37
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