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Brk
.consigliere.

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 Ennesimo esercizio

Ciao, stò leggendo i vecchi temi d'esame...

Qualcuno sa come si risolve questo esercizio?

"Un suono ha una dinamica massima di 96 dB e una dinamicaminima di 48 dB, se la massima ampiezza misura 1, quante volte in meno misura (lineare) la minima ampiezza?

-48
-256
-65536
-Non ci sono abbastanza dati


Grazie e tutti :D

Brk
18-06-2006 11:02
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jackmurnau
.amico.

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credo.. 96/6 -48/6 = 8 ; 2 alla ottava = 256
19-06-2006 18:06
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dodo77
Burn in my Light

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si ma che c'entra 2^8?
da dove è uscito il 2?
20-06-2006 11:03
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Laertes
(lei'3tiz)

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Un raddoppio in ampiezza corrisponde ad un aumento di 6dB.

96/6=16
48/6=8

16-8=8

Significa che l'ampiezza linearmente raddoppia per 8 volte passando da 48dB a 96dB.

Quindi l'ampiezza massima è 2^8 volte quella minima. quindi 256 volte.
24-09-2006 14:51
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